\(=\frac{7^{15}\left(40+9\right)}{7^{17}}=\frac{7^{15}.7^2}{7^{17}}=\frac{7^{17}}{7^{17}}=1\)
Bài giải
\(\left(7^{15}\cdot40+7^{15}\cdot9\right)\text{ : }7^{17}\)
\(=7^{15}\left(40+9\right)\text{ : }7^{17}\)
\(=7^{15}\cdot49\text{ : }7^{17}\)
\(=7^{15}\cdot7^2\text{ : }7^{17}\)
\(=7^{17}\text{ : }7^{17}=1\)