\(260\frac{7}{8}-123\frac{9}{12}\times2=\frac{2087}{8}-\frac{1485}{12}\times2=\frac{2087}{8}-\frac{495}{2}=\frac{107}{8}\)
\(260\frac{7}{8}\)----- \(123\frac{9}{12}\) \(x\)2 = \(\frac{2087}{8}\)------\(\frac{1485}{12}\) \(x\) 2 =\(\frac{2194}{8}\)=274,25