\(\frac{1}{2}+\frac{1}{3}+\frac{1}{6}=\frac{3+2+1}{6}=\frac{6}{6}=1\)
\(\frac{1}{2}+\frac{1}{3}+\frac{1}{6}=\frac{3}{6}+\frac{2}{6}+\frac{1}{6}=\frac{6}{6}=1\)
\(\frac{1}{2}\)+\(\frac{1}{3}\)+\(\frac{1}{6}\)=\(\frac{3}{6}\)+\(\frac{2}{6}\)+\(\frac{1}{6}\)=\(\frac{5}{6}\)+\(\frac{1}{6}\)=\(\frac{6}{6}\)=1
\(\frac{1}{2}\) + \(\frac{1}{3}\)+ \(\frac{1}{6}\) = \(\frac{6}{12}\)+\(\frac{4}{12}\)+\(\frac{2}{12}\)= \(\frac{6+4+2}{12}\)=1