tính
16.64.8^2:(4^3.2^5.16)
(125^3.7^5-175^5:5):2001^2002
Bài 1
c)(125^3.7^5-175^5/5)/2001^2002
d)16.64.8^2/(4^3.2^5.16)
a, \(16.64.8^2:\left[4^3.2^5.16\right]\)
b, \(\left[125^3.7^5-175^5:5\right]:2016^{2017}\)
Tính;
(6^2+7^2+8^2+9^2+10^2)-(1^2+2^2+3^2+4^2+5^2)
(125^3.7^5-175^5:5):2001^2002
16.64.8^2:(4^3.2^5.16)
(125^3.75-175^5:5):2001^2002
16.64.8^2:(4^3.2^5.16)
b, -5 (x+ 1phan5 ) - 1phan2 ( x - 2phan3 ) = 3phan2 * x - 5phan6
Moi nguoi thong cam minh khong biet viet dau phan ten may tinh . Mong moi nguoi giup do,
tinh (125^3.7^5+175^5:5) : 2016^2017
CỨU!!!!!!!!!!!!
Xin loi moi nguoi. Mong moi nguoi tro giup ;-;
(2/3.x + 5/6) . (3/4.x - 27/8) = 0
165-{3.[416-(5^2.3-71)^2]+10^2}:20.Mong nhan duoc su giup do tu moi nguoi!