Các câu hỏi tương tự
1/ Cho A dfrac{1}{3}-dfrac{2}{3^2}+dfrac{3}{3^3}-dfrac{4}{3^4}+.....+dfrac{99}{3^{99}}-dfrac{100}{3^{100}} Chứng minh A dfrac{3}{16}2/ Cho B(dfrac{1}{2^2}-1)(dfrac{1}{3^2}-1)....(dfrac{1}{100^2}-1) So sánh B và dfrac{-1}{2}
Đọc tiếp
1/ Cho A= \(\dfrac{1}{3}\)-\(\dfrac{2}{3^2}\)+\(\dfrac{3}{3^3}\)-\(\dfrac{4}{3^4}\)+.....+\(\dfrac{99}{3^{99}}\)-\(\dfrac{100}{3^{100}}\) Chứng minh A < \(\dfrac{3}{16}\)
2/ Cho B=(\(\dfrac{1}{2^2}\)-1)(\(\dfrac{1}{3^2}\)-1)....(\(\dfrac{1}{100^2}\)-1) So sánh B và \(\dfrac{-1}{2}\)
Chứng minh rằng :100- ( 1+1/2+1/3+...+1/100)=1/2+2/3+3/4+...+99/100
tinh S= 1+1/2(1+2)+1/3(1+2+3)+...+1/100(1+2+3+...+100)
Tinh
A=1+1/2(1+2)+1/3(1+2+3)+...+1/100(1+2+3+...+100)
c/m
a/
1/2!+2/3!+3/4!+...+99/100!<1
b/
1*2-1/2!+2*3-1/3!+3*4-1/4!+...+99*100-1/100!<2
1+ 1/2(1+2) + 1/3(1+2+3) +1/4(1+2+3+4) +....+1/100(1+2+3+..+100)
Ai giúp mk vs .....
Tính tổng:
S = 1 + 1/2 . (1 + 2) + 1/3 . (1 + 2 + 3) + 1/4 . (1 + 2 + 3 + 4) + ... + 1/100 . (1 + 2 + 3 + ... + 99 + 100).
Tính
A=1+1/2(1+2)+1/3(1+2+3)+...+1/100(1+2+3+...+100)
TÍNH F=(1-1/1+2)*(1-1/1+2+3)*(1-1/1+2+3+4)*..........*(1-1/1+2+3+4+.....+2006)
B=(100-1 mũ 2)*(100-2 mũ 2)***(100-50 mũ 2)