Tìm y :\(\left(\frac{1}{24.25}+\frac{1}{25.26}+...+\frac{1}{29.30}\right).120+y:\frac{1}{3}=-4\)
Tìm x
a)\(\left(\frac{1}{24.25}+\frac{1}{25.26}+...+\frac{1}{29.30}\right).120+x:\frac{1}{3}=-4\)
b)\(1\frac{3}{5}+\left(\frac{\frac{2}{7}+\frac{2}{17}+\frac{2}{37}}{\frac{5}{7}+\frac{5}{17}+\frac{5}{37}}\right).x=\frac{16}{5}\)
Tìm x
a/\(\frac{1}{24.25}+\frac{1}{25.26}+...+\frac{1}{29.30}+x\div\frac{1}{3}=-4\)
b/\(\frac{1}{10}+\frac{1}{40}+\frac{1}{88}+...+\frac{1}{\left(3x+2\right)\left(3x+5\right)}=\frac{3}{20}\)
Tìm x biết
\(\frac{1}{24.25}+\frac{1}{25.26}+...+\frac{1}{29.30}+x:\frac{1}{3}=-4\)
\(_{A=\left(\frac{1}{26.25}+\frac{1}{25.26}+...+\frac{1}{29.30}\right).120+x+x:\frac{1}{3}=4}\)
Ai giúp em vs!
tìm y :(1/24.25 + 1/25.26 + ... + 1/29.30) . 120 + y : 1/3 = -4
Tìm y: (1/24.25 + 1/25.26 + ...+ 1/29.30 ) x 120 + y: 1/3 = - 4
a) Tìm số : (\(\frac{1}{24.25}\)+ \(\frac{1}{25.26}\)+ ... + \(\frac{1}{29.30}\)) . 120 + x : \(\frac{1}{3}\)= -4
b) Cho A= \(\frac{3n-5}{n-4}\) (n\(\in\)Z) . Tìm n nguyên để A có giá trị nguyên
\(\left(\frac{1}{25.26}+\frac{1}{26.27}+............+\frac{1}{29.30}\right).150+103\div\left[1.03+\left(x+1\right)\right]=22\)