s=(1-1/4+1/4-1/7+1/7-1/10+...+1/100-1/103)+(1/103-1/104+1/104-1/105+1/105-1/106+1/106-1/107)
=(1-1/103)+(1/103-1/107)
=1 - 1/107
=106/107
s=(1-1/4+1/4-1/7+1/7-1/10+...+1/100-1/103)+(1/103-1/104+1/104-1/105+1/105-1/106+1/106-1/107)
=(1-1/103)+(1/103-1/107)
=1 - 1/107
=106/107
tính tổng s = 3/1.4 + 3/4.7 +3/7.10 +...+ 3/100.103 + 1/103.104 + 1/104.105 + 1/105.106 + 1/106.107
tính tổng S = 3/1.4 + 3/4.7 +3/7.10 +...+ 3/100.103 + 1/103.104 + 1/104.105 + 1/105.106 + 1/106+107
Bài 3 Tính giá trị biểu thức\(\left(1_{ },5\right).\frac{-2}{3}+\left(2,5-\frac{3}{4}\right):1\frac{3}{4}\)
B=\(\frac{1}{1.4}+\frac{1}{4.7}+\frac{1}{7.10}+...+\frac{1}{100.103}\)
Cho S =\(\frac{3}{1.4}+\frac{3}{4.7}+\frac{3}{7.10}+....+\frac{3}{40.43}+\frac{3}{43.46}\)
Hãy C/M S<1
Cho S=\(\frac{3}{1.4}+\frac{3}{4.7}+\frac{3}{7.10}+.....+\frac{3}{40.43}+\frac{3}{43.46}.\)
Hãy chứng tỏ rằng S<1
S=\(\frac{3}{1.4}+\frac{3}{4.7}+\frac{3}{7.10}+...+\frac{3}{40.43}+\frac{3}{43.46}\)
chứng tỏ rằng S<1
Cho S=\(\frac{3}{1.4}+\frac{3}{4.7}+\frac{3}{7.10}+.....+\frac{3}{40.43}+\frac{3}{43.46}\)
Hãy chứng minh S <1
Bài 5: Cho S = \(\frac{3}{1.4}+\frac{3}{4.7}+\frac{3}{7.10}+...+\frac{3}{40.43}+\frac{3}{43.46}\). Hãy chứng tỏ rằng S < 1.
Cho \(S=\frac{3}{1.4}+\frac{3}{4.7}+\frac{3}{7.10}+...+\frac{3}{40.43}+\frac{3}{43.46}\).Hãy chứng tỏ rằng S < 1