\(Q=1-\frac{1}{7}+\frac{1}{7^2}-\frac{1}{7^3}+....-\frac{1}{7^{2013}}\)
\(7Q=7-1+\frac{1}{7}-....-\frac{1}{7^{2012}}\)
\(\Rightarrow8Q=7-\frac{1}{7^{2013}}\Rightarrow Q=\frac{7-\frac{1}{7^{2013}}}{8}\)
\(Q=1-\frac{1}{7}+\frac{1}{7^2}-\frac{1}{7^3}+....-\frac{1}{7^{2013}}\)
\(7Q=7-1+\frac{1}{7}-....-\frac{1}{7^{2012}}\)
\(\Rightarrow8Q=7-\frac{1}{7^{2013}}\Rightarrow Q=\frac{7-\frac{1}{7^{2013}}}{8}\)
tính tổng \(S=\left(-\frac{1}{7}\right)^0+\left(-\frac{1}{7}\right)^1+\left(-\frac{1}{7}\right)^3+\left(-\frac{1}{7}\right)^4+.....+\left(-\frac{1}{7}\right)^{2007}\)
Tính tổng: \(S=\left(\frac{1}{7}\right)^0+\left(\frac{1}{7}\right)^1+\left(\frac{1}{7}\right)^2+...+\left(\frac{1}{7}\right)^{2014}\)
a) Tính tổng: \(S=\left(\frac{-1}{7}\right)^0+\left(\frac{-1}{7}\right)^1+\left(\frac{-1}{7}\right)^2+...+\left(\frac{-1}{7}\right)^{2007}\)
b) Chứng minh rằng : \(\frac{1}{2!}+\frac{2}{3!}+\frac{3}{4!}+...+\frac{99}{100!}
1.Tính tổng :
S = \(\left(\frac{-1}{7}\right)^o+\left(\frac{-1}{7}\right)^1+\left(\frac{-1}{7}\right)^2+...+\left(\frac{-1}{7}\right)^{2017}\)
Tính S = \(\left(\frac{-1}{7}\right)^0+\left(-\frac{1}{7}\right)^1+\left(-\frac{1}{7}\right)^2+.....+\left(-\frac{1}{7}\right)^{2016}\)
tính:\(S=\left(-\frac{1}{7}\right)^0+\left(-\frac{1}{7}\right)^1+...+\left(-\frac{1}{7}\right)^{2007}\)
Tính \(S=\left(-\frac{1}{7}\right)^0+\left(-\frac{1}{7}\right)^1+\left(-\frac{1}{7}\right)^2+...\left(-\frac{1}{7}\right)^{2007}\)
các bạn giúp mình với !!!
Bài 1 Thưc hiện phép tính ( tính nhanh nếu có thể)
a)\(\frac{-1}{24}-\left[\frac{1}{4}-\left(\frac{1}{2}-\frac{7}{8}\right)\right]\)
b)\(\left(\frac{5}{7}-\frac{7}{5}\right)-\left[\frac{1}{2}-\left(\frac{-2}{7}-\frac{1}{10}\right)\right]\)
C)\(\left(\frac{-1}{2}\right)-\left(\frac{-3}{5}\right)+\left(\frac{-1}{9}\right)+\frac{1}{17}-\left(\frac{-2}{7}\right)+\frac{4}{35}-\frac{7}{18}\)
d)\(\left(3-\frac{1}{4}+\frac{2}{3}\right)-\left(5-\frac{1}{3}-\frac{6}{5}\right)-\left(6-\frac{7}{4}+\frac{3}{2}\right)\)
tính S=\(\left(\frac{-1}{7}\right)^0+\left(-\frac{1}{7}\right)^1+...+\left(-\frac{1}{7}\right)^{2007}\)