Question

Tính tổng:

a. x2 + 5x2 + (-3x2)

b. 5xy2 + 1/2 xy2 + 1/4 xy2 + (-1/2 )xy2

c. 3x2y2z2 + x2y2z2

Answer 1

a. x2 + 5x2 + (-3x2) = (1 + 5 – 3)x2 = 3x2

b. 5xy2 + 1/2 xy2 + 1/4 xy2 + (-1/2 )xy2 = (5 + 1/2 + 1/4 - 1/2 )xy2 = 21/4 xy2

c. 3x2y2z2 + x2y2z2 = (3 + 1) x2y2z2 = 4 x2y2z2

Answer 2

a. x2 + 5x2 + (-3x2) = (1 + 5 – 3)x2 = 3x2

b. 5xy2 + 1/2 xy2 + 1/4 xy2 + (-1/2 )xy2 = (5 + 1/2 + 1/4 - 1/2 )xy2 = 21/4 xy2

c. 3x2y2z2 + x2y2z2 = (3 + 1) x2y2z2 = 4 x2y2z2