\(\frac{1}{1.2}+\frac{1}{2.3}+...+\frac{1}{43.44}\)
\(=1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+...+\frac{1}{43}-\frac{1}{44}\)
\(=1-\frac{1}{44}\)
\(=\frac{43}{44}\)
\(\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+...+\frac{1}{43.44}\)
\(=1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+...+\frac{1}{43}-\frac{1}{44}\)
\(=1-\frac{1}{44}\)
\(=\frac{43}{44}\)
đáp án =\(\frac{43}{44}\)
kết bạn với mh nha
\(\frac{1}{1.2}\)\(\frac{1}{2.3}+\frac{1}{3.4}\)+... +\(\frac{1}{43.44}\)= \(1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+...+\frac{1}{43}-\frac{1}{44}\)
= 1-\(\frac{1}{44}\)
=\(\frac{43}{44}\)
ta có:
\(\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+...+\frac{1}{43.44}\)
\(=1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+...+\frac{1}{43}-\frac{1}{44}\)
\(=1-\frac{1}{44}=\frac{43}{44}\)
học tốt nhé!!