Question

tính tổng 200 số hạng đầu tiên của dãy: \(\frac{1}{1.2};\frac{1}{2.3};\frac{1}{3.4};.....\)

Answer 1

\(\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+...+\frac{1}{200.201}\)

\(=1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+...+\frac{1}{200}-\frac{1}{201}\)

\(=1-\frac{1}{201}\)

\(=\frac{200}{201}\)

Answer 2

 \(\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+...+\frac{1}{200.201}\)

\(=\frac{1}{1}-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+...+\frac{1}{200}-\frac{1}{201}\)

\(=1-\frac{1}{201}=\frac{200}{201}\)

Ủng hộ nha,tớ ko ăn cóp đâu.

Answer 3

\(\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+\frac{1}{200.201}\)

\(=\frac{1}{1}-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+...+\frac{1}{200}-\frac{1}{201}\)

\(=\frac{1}{1}-\frac{1}{201}\)

\(=\frac{200}{201}\)

Answer 4

\(\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+.....+\frac{1}{200.201}\)

\(=1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+...+\frac{1}{200}-\frac{1}{201}\)

\(=1-\frac{1}{201}\)

\(=\frac{200}{201}\)