Trả lời
3/1.4+3/4.7+3/7.10
=3/1.3/10
=3/10
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\(\frac{3}{1.4}+\frac{3}{4.7}+\frac{3}{7.10}\)
\(=\frac{1}{1}-\frac{1}{4}+\frac{1}{4}-\frac{1}{7}+\frac{1}{7}-\frac{1}{10}\)
\(=\frac{1}{1}-\frac{1}{10}=\frac{9}{10}\)
\(\frac{3}{1.4}+\frac{3}{4.7}+\frac{3}{7.10}\)
\(=\frac{1}{1}-\frac{1}{4}+\frac{1}{4}-\frac{1}{7}+\frac{1}{7}-\frac{1}{10}\)
\(=\frac{1}{1}-\frac{1}{10}=\frac{10}{10}-\frac{1}{10}\)
\(=\frac{9}{10}\)
\(\frac{3}{1.4}\) + \(\frac{3}{4.7}\) +\(\frac{3}{7.10}\)
= \(\frac{1}{1}\) \(+\frac{1}{4}\) - \(\frac{1}{4}\) + \(\frac{1}{7}\) - \(\frac{1}{7}\) - \(\frac{1}{10}\)
= \(\frac{1}{1}\) - \(\frac{1}{10}\)
= \(\frac{9}{10}\)
\(\frac{3}{1.4}+\frac{3}{4.7}+\frac{3}{7.10}\)
\(=\frac{1}{1}-\frac{1}{4}+\frac{1}{4}-\frac{1}{7}+\frac{1}{7}-\frac{1}{10}\)
\(=\frac{1}{1}-\frac{1}{10}\)
\(=\frac{9}{10}\)