c;=(50-49)(50+49)+(48-47)(48+47)+.............+(2+1)(2-1)
=50+49+48+............+1
=(50+1)50=2550:2=1275
d;=(2^4-1)(2^4+1)(2^8+1)(2^16+1)
=(2^8-1)(2^8+1)(2^16+1)
=(2^16-1)(2^16+1)
=2^32-1
e;=(3-1)(3+1)(3^2+1)...........(3^16+1)
=(3^2-1)(3^2+1)..............(3^16+1)
=(3^16-1)(3^16+1)=3^32-1
tu tinh ket qua luy thua tao khong thua hoi dau
Tính nhanh
a) 5^4×3^4-(15^2-1)*(15^2+1)
b) 50^2-49^2+48^2-47^2+...+2^2-1^2
d) (3^2+1)*(3^4+1)*(3^8+1)
Chứng minh rằng:
a) ( 2 + 1)( 22 + 1)(24 - 1)(28 - 1)(216 + 1) = 232 - 1
b) ( 3 + 1)( 32 + 1)(24 - 1)(38 - 1)(316 + 1) = \(\frac{3^{32}-1}{2}\)
c) 502 + 482 +...+42 + 22 = 492 + 472 +...+ 32 + 12 + 1275
Cho \(A=\dfrac{1}{2}+\dfrac{1}{3}+\dfrac{1}{4}+...+\dfrac{1}{50};B=\dfrac{1}{49}+\dfrac{2}{48}+\dfrac{3}{47}+...+\dfrac{48}{2}+\dfrac{49}{1}\)
Tính giá trị của \(\dfrac{A}{B}\)
a.(2+1)(22+1)(24+1)(28+1)-216=
b.502-492+482-472+...+22-1=
Tính nhanh
a) 2.4.(3^2+1)(3^4+1)...(3^16+1)
b) 2.(3+1).(3^2+1)(3^4+1)...(3^16+1)
c) 8.(3^2+1)(3^4+1)...(3^16+1)
\(\text{ 3(2^2 + 1)(2^4 + 1)(2^8 + 1)(2^{16} + 1)}\) 3(2^2 + 1)(2^4 + 1)(2^8 + 1)(2^16 + 1)
bài 6:tính nhanh
7)1\(^2\)-2\(^2\)+3\(^2\)-4\(^2\)+....-2004\(^2\)+2005\(^2\)
8) (2+1)(2\(^2\)+1)(2\(^4\)+1)(2\(^8\)+1)(2\(^{16}\)+1)(2\(^{32}\)+1)-2\(^{64}\)
BT7: Tính
\(1,A=8\left(3^2+1\right)\left(3^4+1\right)...\left(3^{16}+1\right)\)
\(2,B=\left(1-3\right)\left(3+1\right)\left(3^2+1\right)\left(3^4+1\right)...\left(3^{16}+1\right)\)
Tính nhanh 3(2^2+1)(2^4+1)(2^8+1)(2^16+1)
