Question

Tính nhanh

\(A=\frac{1+2+3+...+200}{6+8+10+...+34}\)

Answer 1

\(=\frac{\left(200+1\right).200:2}{\left(34+6\right).15:2}=\frac{201.200}{40.15}=\frac{201}{3}=67\)

Rồi nha

Hok tốt

Answer 2

\(A=\frac{1+2+3+.....+200}{6+8+10+.....+34}\)

\(A=\frac{\frac{\left[\left(200+1\right).200\right]}{2}}{\frac{\left[\left(34+6\right).15\right]}{2}}\)

\(A=\frac{\frac{200.201}{2}}{\frac{40.15}{2}}=\frac{100.201}{15.20}=\frac{201.10}{15.2}=\frac{2010}{30}=\frac{201}{3}=67\)

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