Question

Tính nhanh

35x12+65x13

(2+4+6+.....100) x( 36x333-108x111)

Answer 1

a) = 35 x 12 + 65 x 12 + 65 = (35 + 65) x 12+ 65 = 100 x 12 + 65 = 1200 + 65 = 1265

b)  (2 + 4 + 6 + ...+ 100) x ( 36 x 3 x 111 - 36 x 3 x 111) =  (2 + 4 + 6 + ...+ 100) x 0 = 0 

Answer 2

35x12+65x13=1265

(2+4+6+.....100) x(36x333-108x111)=0

Answer 3

Ta có

  (2 + 4 + 6 + ...+ 100) x ( 36 x 3 x 111 - 36 x 3 x 111)

=  (2 + 4 + 6 + ...+ 100) x 0

= 0 

hok tốt

Answer 4

b/

(2+4+6+ 7...+100) x (36x3 x111 - 36 x 3 x111)

=(2 + 4 +6...+100 )x 0

= 0

Answer 5

bạn trần thị loan ơi,cho mik hỏi,65 ở cuối cùng chỗ:(35+65)x12+65 ấy!

Answer 6

35x12+65x13 = 35x12+65x(12+1) = 35x12+65x12+65 = 12x(35+65) +65 = 12x100+65 =1200+65 =1265

(2+4+6+...+100)x(36x333-108x111)

=(2+4+6+...+100)x(36x3x111-108x111)

= (2+4+6+...+100)x(108x111-108x111)

=(2=4+6+..+100)x0

=0

Answer 7

35x12+65x13

=35x12+65x12+1

=12.(35+65)+1

=12.100+1

=1200+1

=1201

b) (2+4+6+...+100)x(36x333-108x111)

=A x (11988-11988)

=Ax0

=0

Answer 8

35x12+65x12=(35+65)x12

                      =100x12

                      =1200

(2+4+6+...+100)x(36x333-108x111)=(2+4+6+...+100)x(36x333-(108:3)x(111x3))

                                                        =(2+4+6+...100)x(36x333-36x333)

                                                        =(2+4+6+...+100)x0

                                                        =0