Question

Tính nhanh: Tử số=(1+1/3+1/5+1/7+...+1/97+1/99)x1/5 Mẫu số=2/1x99+2/3x97+2/5x95+...+2/49x51

Answer 1

Tử số=(1+1/3+1/5+1/7+...+1/97+1/99)x1/5 ={ ( 1+1/99) + ( 1/3 + 1/97 ) + ( 1/5 + 1/95) +.....+(1/49 + 1/51)} X 1/5 = (100/ 1 x 99 + 100/ 3 x 97 + 100/ 5 x 95 + ...+ 100/ 49 x 51)X 1/5 = ( 1/1x 99 + 1/ 3 x 97 + 1/ 5 x 95 +...+ 1/ 49 x 51) x 20 Mẫu số=2/1x99+2/3x97+2/5x95+...+2/49x51 = ( 1/1x 99 + 1/ 3 x 97 + 1/ 5 x 95 +...+ 1/ 49 x 51) x 2 Vậy phân số có giá trị = 20/2 = 10