\(A=\frac{3}{1.4}+\frac{3}{4.7}+\frac{3}{7.10}+...+\frac{3}{40.43}+\frac{3}{43.46}\)
\(\Leftrightarrow A=1-\frac{1}{4}+\frac{1}{4}-\frac{1}{7}+\frac{1}{7}-\frac{1}{10}+...+\frac{1}{40}-\frac{1}{43}+\frac{1}{43}-\frac{1}{46}\)
\(\Leftrightarrow A=1-\frac{1}{46}\)
\(\Leftrightarrow A=\frac{45}{46}\)
Các bạn ơi. Chỗ cuối ko có số 4 đâu nha. Mình viết lộn
A = \(\frac{3}{1.4}\)\(+\)\(\frac{3}{4.7}\)\(+\)\(...\)\(+\)\(\frac{3}{43.46}\)
= 1 - \(\frac{1}{4}\)+ \(\frac{1}{4}\) - \(\frac{1}{7}\)+ ...+\(\frac{1}{43}\)- \(\frac{1}{46}\)
= 1 - \(\frac{1}{46}\)
= \(\frac{45}{46}\)