(3965-2378)-(437-1378)-528
=3965-2378-437-1378-528
=(3965-(437+528))-(2378-1378)
=3000-1000
=2000
Bài 1 :
\((3965-2378)-(437-1378)-528\)
\(=3965-2378-437+1378-528\)
\(=3965-(2378-1378)-(437+528)\)
\(=3965-1000-965\)
\(=(3965-965)-1000\)
\(=3000-1000\)
\(=2000\)
Bài 2 :
\((-x+31)-39=-69+11\)
\((-x+31)-39=-58\)
\(-x+31=-58+39\)
\(-x+31=-19\)
\(-x=-19-31\)
\(-x=-50\)
\(=>x=50\)
(-x+31)-39=-69+11
(-x+31)-39=-58
-x+31 =-58+39
-x+31 =-19
-x =-19-31
-x =-50
(3965-2378)-(437-1378)-528
= 3965 - 2378 - 437 - 1378 - 528
= 3965 - ( 2378 - 1378 ) - ( 437 + 528 )
= 3965 - 1000 - 965
= ( 3965 - 965) - 1000
= 3000 - 1000
= 2000
bài 1 :
đề bài: (3965−2378)−(437−1378)−528
Bài giải
=3965−2378−437+1378−528
=3965−(2378-1378)−(437+528)
=3965−1000−965
=(3965−965)−1000
=3000−1000
=2000