\(A=\frac{254.399-145}{254+399.253}\)
\(=\frac{\left(253+1\right).399-145}{254+399.253}\)
\(=\frac{253.399+399-145}{254+399.253}\)
\(=\frac{253.399+254}{254+399.253}=1\)
mk chỉnh đề
\(B=\frac{5932+6001.5931}{5932.6001-69}\)
\(=\frac{5932+6001.5931}{\left(5931+1\right).6001-69}\)
\(=\frac{5932+6001.5931}{5931.6001+5932}=1\)