\(\frac{1999\times\left(2000+1\right)-1}{1998+1999\times2000}\times\frac{7}{5}\Rightarrow\frac{1999\times2000+1999\times1-1}{1998+1999\times2000}\times\frac{7}{5}=\frac{1999\times2000+1998}{1998+1999\times2000}\times\frac{7}{5}=1\Rightarrow1\times\frac{7}{5}=\frac{7}{5}\)