(1/2x4+1/4x6+1/6x8+1/8x10)xy=1/3
Bài 1 tìm y
a) (1/2x4+1/4x6+1/6x8+1/8x10)x y =1/3
b) y:8+y x8-56,78=69,11x2
tìm y:
(2/2x4 + 2/4x6 + 2/6x8 + 2/8x10) x y = 1/3
tìm y :( 1/2x4 + 1/4x6 + 1/6x8 + 1/8x10 ) x y = 1/3
sos cố gắng giúp mik vs . mình cảm ơn
(1phan 2x4+1 phan 4x6+1 phan 6x8+1phan 8x10)xy 1phan 3
Tìm y biết \(\left(\frac{1}{2x4}+\frac{1}{4x6}+\frac{1}{6x8}+\frac{1}{8x10}\right).y=\frac{1}{3}\)
tính:1/2x4+1/4x6+1/6x8+.....+1/96x98+1/98x100=.......
tính : a, 4/2x4+4/4x6+4/6x8+......+4/16x18+4/18x20
b, 1/2+1/6+1/12+1/20+......+1/90
Tính
1/2x4+1/4x6+1/6x8+...+1/96x98+1/98x100=?