Các câu hỏi tương tự
tính
\(\left(\frac{1}{3}+\frac{1}{4}+...+\frac{1}{2009}\right)\left(1+\frac{1}{2}+...+\frac{1}{2008}\right)\)
\(-\left(1+\frac{1}{3}+\frac{1}{4}+...+\frac{1}{2009}\right)\left(\frac{1}{2}+\frac{1}{3}+...+\frac{1}{2008}\right)\)
Tính hợp lí:
(-2).\(\left(-1\frac{1}{2}\right).\left(-1\frac{1}{3}\right).\left(-1\frac{1}{4}\right).........\left(-1\frac{1}{2008}\right)\)
Tính P = \(\left(1+\frac{1}{3}\right)\times\left(1+\frac{1}{2\times4}\right)\times\left(1+\frac{1}{3\times5}\right)\times\left(1+\frac{1}{4\times6}\right)\times...\times\left(1+\frac{1}{2009\times2011}\right)\)
a,tính:A=\(\left(\frac{1}{4}-1\right).\left(\frac{1}{9}-1\right).\left(\frac{1}{16}-1\right).....\left(\frac{1}{100}-1\right).\left(\frac{1}{121}-1\right)\)
b,tình=\(2^{2010}-2^{2009}-2^{2008}-...-2-1\)
giúp với!!!!!♫♪
Tính:
\(\left(-2\right).\left(-1\frac{1}{2}\right).\left(-1\frac{1}{3}\right)...\left(-1\frac{1}{2009}\right).\left(-1\frac{1}{2010}\right)\)
tìm x biết \(\left|x+\frac{1}{2009}\right|+\left|x+\frac{2}{2009}\right|+\left|x+\frac{3}{2009}\right|+...+\left|x+\frac{2008}{2009}\right|\) =2009x
a, Cho H = 22010 - 22009 - 22008 - ......- 2 - 1. Tính 2010H
b, thực hiện phép tính:
\(M=1+\frac{1}{2}\left(1+2\right)+\frac{1}{3}\left(1+2+3\right)+\frac{1}{4}\left(1+2+3+4\right)+......+\frac{1}{16}\left(1+2+3+....+16\right)\)
Bài 1: Tínha. left(1+frac{1}{1cdot3}right)cdotleft(1+frac{1}{2cdot4}right)cdotleft(1+frac{1}{3cdot5}right)+left(1+frac{1}{4cdot6}right).....left(1+frac{1}{99cdot101}right)b. left[sqrt{0,64}+sqrt{0,0001}-sqrt{left(-0,5right)^2}right]divleft[3cdotsqrt{left(0,04right)^2}-sqrt{left(-2right)^4}right]c. frac{5.4^{15}cdot9^9-4.3^{20}cdot8^9}{5cdot2^9cdot6^{19}-7cdot2^{29}cdot27^6}-frac{2^{19}cdot6^{15}-7cdot6^{10}cdot2^{20}cdot3^6}{9cdot6^{19}cdot2^9-4cdot3^{17}cdot2^{26}}+0,left(6right)Bài 2: Tìm x, y...
Đọc tiếp
Bài 1: Tính
a. \(\left(1+\frac{1}{1\cdot3}\right)\cdot\left(1+\frac{1}{2\cdot4}\right)\cdot\left(1+\frac{1}{3\cdot5}\right)+\left(1+\frac{1}{4\cdot6}\right).....\left(1+\frac{1}{99\cdot101}\right)\)
b. \(\left[\sqrt{0,64}+\sqrt{0,0001}-\sqrt{\left(-0,5\right)^2}\right]\div\left[3\cdot\sqrt{\left(0,04\right)^2}-\sqrt{\left(-2\right)^4}\right]\)
c. \(\frac{5.4^{15}\cdot9^9-4.3^{20}\cdot8^9}{5\cdot2^9\cdot6^{19}-7\cdot2^{29}\cdot27^6}-\frac{2^{19}\cdot6^{15}-7\cdot6^{10}\cdot2^{20}\cdot3^6}{9\cdot6^{19}\cdot2^9-4\cdot3^{17}\cdot2^{26}}+0,\left(6\right)\)
Bài 2: Tìm x, y, z biết :
a. \(\left(x-10\right)^{1+x}=\left(x-10\right)^{x+2009}\left(x\in Z\right)\)
b. \(\left|x-2007\right|+\left|x-2008\right|+\left|y-2009\right|+\left|x-2010\right|=3\left(x,y\in N\right)\)
c. \(25-y^2=8\left(x-2009\right)^2\left(x,y\in Z\right)\)
d. \(2008\left(x-4\right)^2+2009\left|x^2-16\right|+\left(y+1\right)^2\le0\)
e. \(2x=3y\) ; \(4z=5x\) và \(3y^2-z^2=-33\)
Bài 3: Chứng minh rằng
a. \(1-\frac{1}{2^2}-\frac{1}{3^2}-\frac{1}{4^2}-...-\frac{1}{2009^2}>\frac{1}{2009}\)
b. \(\left[75\cdot\left(4^{2008}+4^{2007}+4^{2006}+...+4+1\right)+25\right]⋮100\)
Bài 4:
a. Tìm giá trị nhỏ nhất của biểu thức : \(M=\left(x^2+2\right)+\left|x+y-2009\right|+2005\)
b. So sánh: \(31^{11}\) và \(\left(-17\right)^{14}\)
c. So sánh: \(\left(\frac{9}{11}-0,81\right)^{2012}\) và \(\frac{1}{10^{4024}}\)
Kết quả của phép tính \(\left(-2\right)\left(-1\frac{1}{2}\right)\left(-1\frac{1}{3}\right)...\left(-1\frac{1}{2009}\right)\left(-1\frac{1}{2010}\right)\)là .......