Question

Tính hợp lý

(3/5)^10 * (5/3)^10 - 13^4/39^4 + 2017^0

Answer 1

\(\left(\frac{3}{5}\right)^{10}.\left(\frac{5}{3}\right)^{10}-\frac{13^4}{39^4}+2017^0\\ =\left(\frac{3}{5}.\frac{5}{3}\right)^{10}-\left(\frac{13}{39}\right)^4+1\\ =1^{10}-\left(\frac{1}{3}\right)^4+1\)

\(=1-\frac{1}{81}+1\\ =2+\frac{-1}{81}\\ =\frac{161}{81}\)

Answer 2

(3/5)^10.(5/3)^10-13^4/39^4+2017^0

=1-1/81+1

=161/81