\(=\frac{5.-36}{13.15}=\frac{1.-36}{13.3}=\frac{1.-12}{13.1}=-\frac{12}{13}\)
\(=\frac{5.-36}{13.15}=\frac{1.-36}{13.3}=\frac{1.-12}{13.1}=-\frac{12}{13}\)
so sánh = cách hợp lí
P1 =\(\left(-\frac{43}{51}\right)\cdot\left(\frac{-19}{80}\right)\)
P2 = \(\left(-\frac{7}{13}\right)\cdot\left(-\frac{4}{65}\right)\cdot\left(-\frac{8}{31}\right)\)
P3= \(-\frac{5}{10}\cdot-\frac{4}{10}\cdot-\frac{3}{10}....\frac{3}{10}\cdot\frac{4}{10}\cdot\frac{5}{10}\)
Tìm x:
\(\frac{\left(13\frac{2}{9}-15\frac{2}{3}\right)\cdot\left(30^2-5^4\right)}{\left(18\frac{3}{7}-17\frac{1}{4}\right)\cdot\left(25-12\cdot5^2\right)}\cdot x=\frac{\frac{2}{11}+\frac{3}{13}+\frac{4}{15}+\frac{5}{17}}{4\frac{1}{11}+\frac{5}{13}+\frac{9}{15}+\frac{13}{17}}\)
Tính nhanh:
a,\(\frac{7}{13}\cdot\frac{7}{15}-\frac{5}{12}\cdot\frac{21}{39}+\frac{49}{91}\cdot\frac{8}{15}\)
b,\(\left(\frac{12}{199}+\frac{23}{200}-\frac{34}{201}\right)\cdot\left(\frac{1}{2}-\frac{1}{3}-\frac{1}{6}\right)\)
tính nhanh
a, \(\frac{-2}{5}\cdot\left(\frac{5}{17}-\frac{9}{15}\right)-\frac{2}{5}\cdot\frac{2}{17}+\frac{-2}{5}\)
b, \(\frac{1}{5}\cdot\left(\frac{4}{13}-\frac{9}{11}\right)+\frac{1}{3}\left(\frac{9}{13}-\frac{4}{22}\right)\)
c, \(\left(\frac{1}{2}+1\right)\cdot\left(\frac{1}{3}+1\right)\cdot\left(\frac{1}{4}+1\right)\cdot...\cdot\left(\frac{1}{99}+1\right)\)
d, \(\left(1-\frac{1}{2}\right)\cdot\left(1-\frac{1}{3}\right)\cdot\left(1-\frac{1}{4}\right)\cdot...\cdot\left(1-\frac{1}{100}\right)\)
\(\frac{1}{3}-\frac{3}{5}+\frac{5}{7}-\frac{7}{9}+\frac{9}{11}-\frac{11}{13}+\frac{13}{15}+\frac{11}{13}-\frac{9}{11}+\frac{7}{9}-\frac{5}{7}+\frac{3}{5}-\frac{1}{3}\)
thực hiện phép tính hợp lí nếu có thể
câu này cũng tính hợp lí luôn nha:
F=\(\left(9\cdot75\cdot21\frac{3}{7}+\frac{39}{4}\cdot18\frac{4}{7}\right)\cdot\frac{15}{78}\)
Tính bằng cách hợp lí
A=\(\frac{1}{3}-\frac{3}{4}-\left(-\frac{3}{5}\right)+\frac{1}{64}-\frac{2}{9}-\frac{1}{36}+\frac{1}{15}\)
Tính hợp lí: \(\frac{12}{9}.\frac{7}{15}.\frac{-13}{17}.\frac{19}{12}.\frac{17}{13}\)
\(\left(X-\frac{5}{8}\right)\cdot\frac{5}{18}=\frac{_{-15}}{36}\)