\(\frac{4}{7}\times\frac{1}{3}+\frac{5}{7}:\frac{2}{3}\)
\(=\frac{4}{21}+\frac{5}{7}\times\frac{3}{2}\)
\(=\frac{4}{21}+\frac{15}{14}\)
\(=\frac{4\times2}{21\times2}+\frac{15\times3}{14\times3}\)\(=\frac{8}{42}+\frac{45}{42}=\frac{8+45}{42}=\frac{53}{42}\)