Question

Tính giá trị biểu thức:

\(\text{E}=\frac{\frac{1}{6}-\frac{1}{39}+\frac{1}{51}}{\frac{1}{8}-\frac{1}{52}+\frac{1}{68}}\)

Answer 1

Xét : 1/8 - 1/52 + 1/68

= 3/4 . 1/6 - 3/4 . 1/39 + 3/4 . 1/68

= 3/4 . (1/6-1/39+1/51)

=> E = 1/(3/4) = 4/3

Tk mk nha

Answer 2

\(\text{E}=\frac{\frac{1}{6}-\frac{1}{39}+\frac{1}{51}}{\frac{1}{8}-\frac{1}{52}+\frac{1}{68}}\)

\(\text{E}=\frac{\frac{1}{6}-\frac{1}{39}+\frac{1}{51}}{\frac{3}{4}.\frac{1}{6}-\frac{3}{4}.\frac{1}{39}+\frac{3}{4}.\frac{1}{68}}\)

\(\text{E}=\frac{\frac{1}{6}-\frac{1}{39}+\frac{1}{51}}{\frac{3}{4}\left(\frac{1}{6}-\frac{1}{39}+\frac{1}{51}\right)}\)

\(\text{E}=\frac{1}{\left(\frac{3}{4}\right)}=\frac{4}{3}\)