co |x - 2| + (y - 1)^2 = 0
|x - 2| > 0 va (y - 1)^2 > 0
=> |x - 2| = 0 va (y - 1)^2 = 0
=> x - 2 = 0 va y - 1 = 0
=> x = 2 va y = 1
P = 3x + x - y/x + 4
P = 3(x + 1) - y/x + 4
P = 3(2 + 1) - 1/2 + 4
P = 8/6 = 4/3
cho xyz la cac so thuc thoa man y+z+1/x=x+z+2/y=x+y+2/z=1/x+y+z tinh gia tri bieu thuc A=2016.x+y^2017+z^2017
Tinh GT bieu thuc M = 21x2y + 4xy2 voi x,y thoa man :
(x-2)4-(2y-1)2014 < hoac =4
Tinh gia tri bieu thuc:
a)A=5x+8xy+5y voi x+y=2/5;xy=3/4
b)B=2xy+7xyz-2xz voi x=3/7;y-z=5/2;y.z=-1
tinh gia tri cua bieu thuc x-y=0 sao cho x.(x^2+y^2)+y.(-y^2-X^2)+5
1. so x>0 thoa man \(\frac{5}{x}=\frac{x+1}{22}\)
2. GTLN cua x thoa man \(5^{\left(x-2\right)\left(x+3\right)}\)
3. Gia tri x<0 thoa man /\(x^2+50\)/=/\(-2x^2\)-1/
4. Gia tri nguyen cua x thoa man \(\left(3x-4\right)^5\)=\(^{\left(3x-4\right)^7}\)la x=
5. So gia tri cua x thoa man /x-2014/+/x-2015/=0
6. Gia tri cua x de bieu thuc A=\(\frac{x-3+5}{3-x+2}\)dat gia tri lon nhat la x=
cho x,y,z la cac so huu ti duong thoa man x+1/yz y +1/xz z+1/xy la cac so nguyen tim gia tri lon nhat cua bieu thuc A=x+y^2+z^3
tinh gia tri bieu thuc:
a,3x^4+5x^2y^2+2y^4+2y^2 biet rang x^2+y^2=1
tinh gia tri bieu thuc:
a,3x^4+5x^2y^2+2y^4+2y^2 biet rang x^2+y^2=1
tinh gia tri bieu thuc:
a,3x^4+5x^2y^2+2y^4+2y^2 biet rang x^2+y^2=1
