Question

Tính giá trị biểu thức :

     \(H=9^{\frac{1}{\log_63}}+4^{\frac{1}{\log_82}}-10^{\log99}\)

Answer 1

\(I=9^{\frac{1}{\log_63}}+4^{\frac{1}{\log_82}}-10^{\log99}=\left(3^2\right)^{\log_36}+\left(2^2\right)^{\log_28}-99\)

   \(=3^{\log_36^2}+2^{\log_38^2}-99=6^2+8^2-99=1\)