Ta có (2 + x) + (4 + x) + (6 + x) +..........+ (52 + x) = 780
=> (2 + 4 + 6 + ....... + 52) + (x + x + x + ....... + x) = 780
=> 702 + 26x = 780
=> 26x = 78
=> x = 3
Vậy x = 3
Ta có (2 + x) + (4 + x) + (6 + x) +..........+ (52 + x) = 780
=> (2 + 4 + 6 + ....... + 52) + (x + x + x + ....... + x) = 780
=> 702 + 26x = 780
=> 26x = 78
=> x = 3
Vậy x = 3
Ta có (2 + x) + (4 + x) + (6 + x) +..........+ (52 + x) = 780
=> (2 + 4 + 6 + ....... + 52) + (x + x + x + ....... + x) = 780
=> 702 + 26x = 780
=> 26x = 78
=> x = 3
Vậy x = 3