Ta có:\(A=\frac{1}{1.3}+\frac{1}{3.5}+...+\frac{1}{2009.2011}\)
\(2A=2.\left(\frac{1}{1.3}+\frac{1}{3.5}+...+\frac{1}{2009.2011}\right)=\frac{2}{1.3}+\frac{2}{3.5}+...+\frac{2}{2009.2011}\)
\(=\frac{1}{1}-\frac{1}{3}+\frac{1}{3}-\frac{1}{5}+...+\frac{1}{2009}-\frac{1}{2011}\)
\(=1-\frac{1}{2011}=\frac{2010}{2011}\)
=>\(A=\frac{2010}{2011}:2=\frac{2010}{2011}.\frac{1}{2}=\frac{1005}{2011}\)