Question

tính diện tích hình tứ giác MBND biết hình chữ nhật ABCD có DC=36cm;AD=20cm;AM=1\3MB;BN=NC

Answer 1

\(S_{MBND}=S_{ABCD}-S_{AMD}-S_{NCD}\)

\(S_{ABCD}=36\times20=720\left(cm^2\right)\)

\(AM=\frac{1}{3}MB\Rightarrow AM=\frac{1}{4}AB=\frac{1}{4}CD=9\left(cm\right)\)

\(BN=NC\Rightarrow NC=\frac{1}{2}BC=\frac{1}{2}AD=10\left(cm\right)\)

\(S_{AMD}=\frac{1}{2}AM\times AD=\frac{1}{2}\times20\times9=90\left(cm^2\right)\)

\(S_{NCD}=\frac{1}{2}NC\times CD=\frac{1}{2}\times10\times36=180\left(cm^2\right)\)

Answer 2

999999999999999999999999999999999

Answer 3

bằng 999999999999999999