ta có \(\frac{1}{13}+\frac{16}{7}+\frac{3}{105}-\frac{9}{7}-\left(-\frac{12}{13}\right)\)
\(=\left[\frac{1}{13}-\left(-\frac{12}{13}\right)\right]+\left(\frac{16}{7}-\frac{9}{7}\right)+\frac{3}{105}\)
\(=1+1+\frac{3}{105}\)
\(=2+\frac{3}{105}=2\frac{3}{105}\)