\(a,\frac{2001}{2002}.\frac{5}{7}.\frac{2002}{5}.\frac{7}{2001}=\left(\frac{2001}{2002}.\frac{7}{2001}\right).\left(\frac{5}{7}.\frac{2002}{5}\right)\)
\(=\frac{7}{2002}.\frac{2002}{7}=1\)
\(b,\frac{5}{7}.\frac{7}{9}.\frac{9}{11}.\frac{11}{13}=\left(\frac{5}{7}.\frac{7}{9}\right).\left(\frac{9}{11}.\frac{11}{13}\right)=\frac{5}{9}.\frac{9}{13}\)
\(=\frac{5}{13}\)
xin lỗi mình k nhầm
Mai mình k trả lại
a) \(\frac{2001}{2002}.\frac{5}{7}.\frac{2002}{5}.\frac{7}{2001}\)
\(=\frac{2001.5.2002.7}{2002.7.5.2001}\)
\(=1\)
b) \(\frac{5}{7}.\frac{7}{9}.\frac{9}{11}.\frac{11}{13}\)
\(=\frac{5.7.9.11}{7.9.11.13}\)
\(=\frac{5}{13}\)
a) \(\frac{2001}{2002}\cdot\frac{5}{7}\cdot\frac{2002}{5}\cdot\frac{7}{2001}\)
\(=\frac{2001\cdot5\cdot2002\cdot7}{2002\cdot7\cdot5\cdot2001}\)
\(=1\)
b) \(\frac{5}{7}\cdot\frac{7}{9}\cdot\frac{9}{11}\cdot\frac{11}{13}\)
\(=\frac{5\cdot̸7\cdot̸9\cdot̸1̸1}{̸7\cdot̸9\cdot̸1̸1\cdot13}\)
\(=\frac{5}{13}\)
a, 1
b, \(\frac{5}{13}\)
a )\(1\)
b ) \(\frac{5}{13}\)
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