a, C1: \(4\frac{3}{7}.2=\frac{31}{7}.2=\frac{31.2}{7}=\frac{62}{7}=8\frac{6}{7}\)
C2: \(4\frac{3}{7}.2=\left(4+\frac{3}{7}\right).2=\left(4.2\right)+\left(\frac{3}{7}.2\right)=8+\frac{6}{7}=8\frac{6}{7}\)
b, C1: \(\frac{11}{2}.3=\frac{11.3}{2}=\frac{33}{2}=16\frac{1}{2}\)
C2: \(5\frac{1}{2}.3=\left(5+\frac{1}{2}\right).3=\left(5.3\right)+\left(\frac{1}{2}.3\right)=15+1\frac{1}{2}=16\frac{1}{2}\)