\(\Rightarrow B=\frac{2^{15}.7-2^{15}.2}{5.2^{15}}\)
\(\Rightarrow B=\frac{2^{15}.\left(7-2\right)}{5.2^{15}}\)
\(\Rightarrow B=\frac{2^{15}.5}{5.2^{15}}=1\)
Giải :
\(B=\frac{2^{15}.7-2^{16}}{5.2^{15}}=\frac{2^{15}\left(7-2\right)}{5.2^{15}}=\frac{2^{15}.5}{5.2^{15}}=1\)
Vậy B = 1
\(B=\frac{2^{15}.7-2^{15}.2}{5.2^{15}}=\frac{2^{15}.\left(7-2\right)}{5.2^{15}}=\frac{2^{15.5}}{5.2^{15}}=1\)
B=215.7-215.2/5.215
B=215.(7-2)/5.215
B=215.5/5.215
B=1
k cho mk nhé