mk ko viết lại đề
\(A=\frac{2^{12}.3^5-2^{12}.3^4}{2^{12}.3^6+2^{12}.3^5}+\frac{2^{12}.3^{10}+2^{12}.3^{10}.5}{2^{12}.3^{12}+2^{12}.3^{12}}\)
\(=\frac{2^{12}.3^4\left(3-1\right)}{2^{12}.3^5\left(3+1\right)}+\frac{2^{12}.3^{10}\left(1+5\right)}{2.\left(2^{12}.3^{12}\right)}\)
\(=\frac{2}{3.4}+\frac{2^{12}.3^{10}.6}{2.2^{12}.3^{12}}=\frac{1}{6}+\frac{1}{3}=\frac{1}{2}\)
Vậy A= \(\frac{1}{2}\)
Tính B=\(\frac{\left(\frac{2}{3}\right)^3.\left(\frac{-3}{4}\right)^2.\left(-1\right)^5}{\left(\frac{2}{5}\right)^2.\left(\frac{5}{12}\right)^2}-\frac{4^6.9^5+6^9.120}{8^4.3^{12}-6^{11}}\)
giúp mình giải chi tiết nha các bạn mai mình phải nộp rồi
tính\(\frac{2^{12}.3^5-4^6.9^2}{\left(2^2.3\right)^6+8^4.3^5}-\frac{5^{10}.7^3-25^2.49^2}{\left(125.7\right)^3+5^9.14^3}\)
tính
A=\(\frac{2^{12}.3^5-4^6.9^2}{\left(2^2.3\right)^6+8^4.3^5}\)- \(\frac{5^{10}.7^{3-25^5.49^2}}{\left(\left(125.7\right)^3\right)+5^9.14^3}\)
Rút gọn :
A = \(\frac{2^{12}.3^5-4^6.9^2}{\left(2^2.3\right)^6+8^4.3^5}-\frac{5^{10}.7^3-25^5.49^2}{\left(125.7\right)^3+5^9.\left(14\right)^3}\)
Tính giá trị của biểu thức A
\(A=\frac{2^{12}.3^5-4^6.9^2}{\left(2^2.3\right)^6+8^4.3^5}-\frac{5^{10}.7^3-25^5.49^2}{\left(125.7\right)^3+5^9.14^3}\)
tính giá trị các biểu thức sau
\(A=\frac{4^6.9^5+6^9.120}{-8^4.3^{12}+6^{11}}\) \(B=\frac{5.\left(2^2.3^2\right)^9.\left(2^2\right)^6-2.\left(2^2.3\right)^{14}.3^{4.}}{5^2.2^{28}.3^{18}-7.2^{29}.3^{18}}\)
\(C=\frac{5^2.6^{11}.6^{12}+6^2.12^6.15^2}{2.6^{12}.10^4+81^2.960^3}\) \(D=\frac{11.3^{22}.3^2-9^{15}}{\left(2.3^{14}\right)^2}\)
Tính giá trị biểu thức sau:
1/ \(\frac{9.5^{20}.27^9-3.9^{15}.25^9}{7.3^{29}.125^6-3.3^9.15^{19}}\).
2/ \(\frac{5.\left(2^2.3^2\right)^9.\left(2^2\right)^6-2.\left(2^2.3\right)^{14}.3^6}{5.2^{28}.3^{19}-7.2^{29}.3^{18}}\)
3/ \(\frac{2^{12}.13+2^{12}.65}{2^{10}.104}+\frac{3^{10}.11+3^{10}.5}{3^9.2^4}\)
4/ \(\frac{5.4^{15}-9^9-4.3^{20}.8^9}{5.2^9.6^{19}-7.2^{29}.27^6}\)
5/ \(\frac{13.4^6.\left(28\frac{7}{13}-27\frac{5}{18}\right)}{59.2^{12}\left(\frac{5}{14}+\frac{5}{84}+\frac{5}{204}+\frac{5}{374}\right)}\)
Tặng người giải mỗi ngày ba điểm hđ :)
Tính \(\frac{16^3.3^{10}+120.6^9}{4^6.3^{12}+6^{11}}\)
a) Tính
A=\(\frac{2^{12}.3^5-4^6.9^2}{\left(2^2.3\right)^6+8^4.3^5}-\frac{5^{10}.7^3-2^5.49^2}{\left(125.7\right)^3+5^9.14^3}\)
b) Chứng tỏ với mọi số nguyên n thì:
\(3^{n-2}-2^{n+2}+3^n-2^n⋮10\)
