Question

Tính :

a,A = 100²+200²+300²+...+1000²

b,\(B=\frac{4^9.36+64^4}{16^4.100}\)

Answer 1

A=100²(1+2²+3²+....+10²)=100².375=375.10⁴

B=\(\frac{4^{8^{ }}.4.6^2+4^{8^{ }}.4^4}{4^8.10^2}\)=\(\frac{4^{8^{ }}.2^2.6^2+4^{8^{ }}.4^4}{4^8.10^2}\)=\(\frac{4^{8^{ }}.2^2.6^2+4^8.2^2.2^6}{4^8.2^2.5^2}\)=\(\frac{4^8.2^2\left(6^2+2^6\right)}{4^8.2^2.5^2}\)=\(\frac{6^2+2^6}{5^2}\)

 

 

 

 

B=4⁸.4.6²+4⁸.4⁴:4⁸.10²