Question

Tính : \(A=2^0+2^3+2^5+...+2^{99}.\). Giá trị của A là ...

Answer 1

\(A=2^0+2^3+2^5+...+2^{99}\)

\(A\cdot2^2=2^2+2^5+2^7+...+2^{101}\)

\(A\cdot3=2^2-1+2^{99}\)

Answer 2

\(\text{A}=1+2^3+2^5+....+2^{99}\)

\(4\text{A}=2+2^5+2^8+.....+2^{101}\)

\(4\text{A}-\text{A}=\left(2+2^5+2^8+....+2^{101}\right)-\left(1+2^3+...+2^{99}\right)\)

\(3\text{A}=2^{101}+2^2-2^3+2^0\)