dãy số 2, 6, 12, 20...9900 tách ra thành 1.2, 2.3, 3.4, 4.5,..., 99.100
nghĩa là mình có công thức ∑ (i=1 -> 99) (2010) / (99.(99+1))
(2010). ∑(i=1 -> 99) (99/100)
2010 . (99/100) = 1989,9
tick nha
\(\frac{2010}{2}+\frac{2010}{6}+\frac{2010}{12}+.....+\frac{2010}{9900}\)
TÍNH TỔNG
Tính A = \(\frac{2010}{2}\) +\(\frac{2010}{6}\) +\(\frac{2010}{12}\) +..........+\(\frac{2010}{9900}\)
Giup minh nhe 2 ngay nua phai nop roi !
Cho tam giac ABC deu . M la mot diem trong tam giac sao cho MA:MB:MC=3:4:5 . Tinh so do goc AMB .
C2 : Tinh A = 2010/2+2010/6+2010/12 +....+2010/9900
Rút gọn
A=\(\frac{3^{2010}-6^{2010}+9^{2010}-12^{2010}+15^{2010}-18^{2010}}{1+2^{2010}-3^{2010}+4^{2010}-5^{2010}+6^{2010}}\)
rút gọn biểu thức: P=\(\frac{3^{2010}-6^{2010}+9^{2010}-12^{2010}+15^{2010}-18^{2010}}{-1+2^{2010}-3^{2010}+4^{2010}-5^{2010}+6^{2010}}\)
A= 2010/ 2 + 2010/ 6+ 2010/ 12 +.............+
tính:
B=\(\frac{1^{2010}+2^{2010}+3^{2010}+...+10^{2010}}{2^{2010}+4^{2010}+6^{2010}+...+20^{2010}}\)
mik cần gấp, trước 10:15
Rút gọn:
32020 - 62010 + 92010 - 122010 + 152010 - 182010
-1 + 22010 - 32010 + 42010 - 52010 + 62010
Choa,b,c,d khác 0:
\(\frac{x^{2010}+y^{2010}z^{2010}+t^{2010}}{a^2+b^2+c^2+d^2}=\frac{x^{2010}}{a^2}+\frac{y^{2010}}{b^2}+\frac{z^{2010}}{c^2}+\frac{t^{2010}}{d^2}\)
Tính\(T=x^{2010}+y^{2010}+z^{2010}+t^{2010}\)
