Tính:
a, \(\dfrac{x-1}{x+2}+\dfrac{x+5}{x+2}=\dfrac{x-1+x+5}{x-2}=\dfrac{2x+4}{x-2}\) = \(\dfrac{2\left(x+2\right)}{x-2}\)
b, \(\dfrac{1}{x\left(x-1\right)}-\dfrac{2-x}{x-1}=\dfrac{1}{x\left(x-1\right)}-\dfrac{x\left(2-x\right)}{x\left(x-1\right)}=\dfrac{1-2x+x^2}{x\left(x-1\right)}=\dfrac{x^2-2x+1}{x\left(x-1\right)}=\dfrac{\left(x-1\right)^2}{x\left(x-1\right)}=\dfrac{x-1}{x}\)