Các câu hỏi tương tự
Tính :
\(A=\frac{1^2}{1^2-100+5000}+\frac{2^2}{2^2-200+5000}+...+\frac{99^2}{99^2-9900+5000}\)
\(\frac{1^2}{1^2-100+5000}+\frac{2^2}{2^2-200+5000}+........+\frac{99^2}{99^2-9900+5000}\)
1. tính:
A= \(\frac{1^2}{1^2-100+5000}+\frac{2^2}{2^2-200+5000}+...+\frac{99^2}{99^2-9900+5000}\)
giải nhanh nhé
Tính A= (1^2/1^2-100+5000)+(2^2/2^2-200+5000)+...+(99^2/99^2-9900+5000)
Tính tổng
M = \(\left(1-\frac{1}{1-2010}\right)\left(2-\frac{1}{1-\frac{2010}{2}}\right)\left(3-\frac{1}{1-\frac{2010}{3}}\right)....\left(5000-\frac{1}{1-\frac{5000}{3}}\right)\)
Tính A = 12/(12-100+5000) + 22/(22-100+5000) + ... +992/(992-100+5000)
Ai hoc gioi giai giup minh
tính
M=(1-\(\frac{1}{1-\frac{2010}{1}}\)) . (2-\(\frac{1}{1-\frac{2010}{2}}\)) ...... (5000-\(\frac{1}{1-\frac{2010}{5000}}\))
Cho A = \(\frac{2^2-1^2}{2^2}+\frac{3^2-2^2}{6^2}+\frac{4^2-3^2}{12^2}+.....+\frac{100^2-99^2}{9900^2}\)
Chứng minh A < 1
4 tháng 2 2017 lúc 1:27
1) Hãy tính:A (1 + 2 +3 + ... + 100) - (frac{1}{2}+ frac{2}{3}+ frac{3}{4}+ ... + frac{49}{50})B( frac{1}{2frac{3}{4}}+ frac{1}{3frac{4}{5}}+ frac{1}{4frac{5}{6}}+ ... + frac{1}{98frac{99}{100}}) - ( frac{1}{2}. frac{3}{4}frac{5}{6}... frac{99}{100})2) Tìm x để:a) left(x+10right).left(x+20right)...left(x+500right)5000000b) frac{1}{2}x + frac{3}{4}x + ... + frac{100}{101}x 5000frac{sqrt{x-5}}{45}. frac{frac{6}{7}}{sqrt{4^{75}}+25} - left(frac{4}{5}+frac{6}{7}+...+frac{50}{51}right) 300x
Đọc tiếp
1) Hãy tính:
A= (1 + 2 +3 + ... + 100) - (\(\frac{1}{2}\)+ \(\frac{2}{3}\)+ \(\frac{3}{4}\)+ ... + \(\frac{49}{50}\))
B=( \(\frac{1}{2\frac{3}{4}}\)+ \(\frac{1}{3\frac{4}{5}}\)+ \(\frac{1}{4\frac{5}{6}}\)+ ... + \(\frac{1}{98\frac{99}{100}}\)) - ( \(\frac{1}{2}\). \(\frac{3}{4}\)\(\frac{5}{6}\)... \(\frac{99}{100}\))
2) Tìm x để:
a) \(\left(x+10\right).\left(x+20\right)...\left(x+500\right)=5000000\)
b) \(\frac{1}{2}\)\(x\) + \(\frac{3}{4}\)\(x\) + ... + \(\frac{100}{101}\)\(x\) = \(5000\)
\(\frac{\sqrt{x-5}}{45}\). \(\frac{\frac{6}{7}}{\sqrt{4^{75}}+25}\) - \(\left(\frac{4}{5}+\frac{6}{7}+...+\frac{50}{51}\right)\) = \(300x\)