Question

tính : 

a. A = 1.4 + 2.5 + 3.6+...+ 99.102

b. B = 1.3+2.4+3.5 +...+99.101

c. C = 4 + 12 + 24 + 40 +...+ 19404 + 19800

Answer 1

\(A=1.\left(2+2\right)+2.\left(3+2\right)+3.\left(4+2\right)+....+99.\left(100+2\right)\)

\(A = (1.2 + 2.3 + 3.4 + ... + 99.100) + (1.2 + 2.2 + 3.2 + ... + 99.2)\)
\(Đặt B = 1.2 + 2.3 + 3.4 + ... + 99.100\)
\(3B = 1.2.(3-0) + 2.3.(4-1) + 3.4.(5-2) + ... + 99.100.(101-98)\)
\(3B = 1.2.3 - 0.1.2 + 2.3.4 - 1.2.3 + 3.4.5 - 2.3.4 + ... + 99.100.101 - 98.99.100\)
\(3B = 99.100.101\)
\(B = 33.100.101 = 333300\)
\(A = 333300 + 2.(1 + 2 + 3 + ... + 99)\)
\(A = 333300 + 2.(1 + 99).99:2\)
\(A = 333300 + 100.99\)
\(A = 333300 + 9900\)
\(A = 343200\)

Answer 2

a. A = 1.4 + 2.5 + 3.6 +...+ 99.102

       = 1( 2 +2) + 2(3+2) +...+ 99 (100 +2)

       = 1.2 + 1.2 +2.3 + 2.2 +...+ 99 .100 +99 . 2

       = ( 1.2 +2.3 + 3.4 +...+99 . 100) + 2(1 + 2 + 3+...+99)

       = 333300 + 9900 = 343 200

b. B = 1.3 + 2.4 + 3.5 +...+ 99.101

       = 1(2 +1) + 2(3 +1) + 3(4 +1) +...+ 99(100 +1)

       = 1.2 + 1 + 2.3 + 2 + 3.4 +...+ 99. 100 +99

       = ( 1.2 + 2.3 + 3.4 +...+ 99.100) + (1+2+...+99)

       = 333300 + 4950 = 338 250

c. C = 4 + 12 + 24 +...+ 19404 + 19800

  1/2C = 1.2 + 2.3 + 3.4 +...+ 98.99 + 99.100

1/2 C  = 333300 

    C   = 333300 : 1/2 = 666600