\(a,3\frac{3}{4}+15\frac{1}{2}=\frac{15}{4}+\frac{31}{2}=\frac{15}{4}+\frac{62}{4}=\frac{77}{4}\)
\(b,80\frac{1}{4}-72=8\frac{1}{4}=\frac{33}{4}\)
\(c,2\frac{1}{6}.7\frac{6}{5}=\frac{13}{6}.\frac{41}{5}=\frac{533}{30}\)
\(d,30\frac{1}{2}:\frac{1}{25}=\frac{61}{2}:\frac{1}{25}=\frac{61.25}{2}=\frac{1525}{2}\)
a,\(3\frac{3}{4}+15\frac{1}{2}=3,75+15,05=18,8\)
b,\(80\frac{1}{4}-72=80,25-72=8,25\)
c,\(2\frac{1}{6}\times7\frac{6}{5}=\frac{13}{6}\times\frac{41}{5}=\frac{533}{30}\)
d,\(30\frac{1}{2}:\frac{1}{25}=\frac{61}{2}\times25=\frac{1525}{2}\)
a) \(3\frac{3}{4}+15\frac{1}{2}=3\frac{3}{4}+15\frac{2}{4}=19\frac{1}{4}\)
b) \(80\frac{1}{4}-72=8\frac{1}{4}\)
c) \(2\frac{1}{6}\cdot7\frac{6}{5}=\frac{13}{6}\cdot\frac{41}{5}=\frac{533}{30}\)
d) \(30\frac{1}{2}\div\frac{1}{25}=\frac{61}{2}\cdot25=\frac{1525}{2}\)