Question

Tính : 21 - 20 - 19 + 18 + 17 - 16 - 15 + 14 + ... + 5 - 4 - 3 + 2 + 1

Answer 1

(21-20)-(19-18)+(17-16)-(15-14)+...+(5-4)-(3-2)+1=1-1+1-1+...+1-1+1=(1-1)+(1-1)+...+(1-1)+1( có 10 cặp nhóm)

=0+0+...+0+0+1=1.

Answer 2

Giải:

      \(21-20-19+18+17-16-15+14+...+5-4-3+2+1\)

\(=\left(21-20-19+18\right)+\left(17-16-15+14\right)+...+\left(5-4-3+2\right)+1\)

\(=0+0+...+0+1=1\)

Answer 3

10 do ban a cho minh nha