\(100x^2-20x+1\)
\(=\left(10x\right)^2-2.10x.1+1^2\)
\(=\left(10x-1\right)^2\)
\(=\left(0-1\right)^2=1\)
thayx=0, co
100.0^2-20.0+1
=100.0-20.0+1
=0-0+1
=1
\(100x^2-20x+1\)
\(=\left(10x\right)^2-2.10x.1+1^2\)
\(=\left(10x-1\right)^2\)
\(=\left(0-1\right)^2=1\)
100x2 - 20x + 1
= (10x)2 - 2.10x.1 + 12
= (10x - 1)2 (1)
Thay x = 0 vào (1), ta có:
(10.0 - 1)2 = (0 - 1)2
= (-1)2 = 1
\(100x^2-20x+1\)
\(=\left(10x-1\right)^2\)
\(=\left(0-1\right)^2\)
\(=1\)
