\(\frac{1+2y}{18}=\frac{1+4y}{24}=\frac{1+6y}{6x}TÌM:X;Y\)
Tìm x,y\(\in\)Z, biết:
\(\frac{x}{6}-\frac{1}{y}=\frac{1}{2}\)
tìm x
\(\frac{1}{6}.x+\frac{1}{10}-\frac{4}{15}.x+1=0\)
tìm x, y \(\in\)Z
\(\frac{5}{x}+\frac{4}{y}=\frac{1}{8}\)
Tìm x,y là số nguyên:
a, \(\frac{1}{x}=\frac{1}{6}+\frac{y}{3}\)
b, \(\frac{x}{6}-\frac{1}{y}=\frac{1}{2}\)
1a)tìm x,y biết: \(4+\frac{x}{7+y}=\frac{4}{7}and:x+y=22\)
b)cho \(\frac{x}{3}=\frac{y}{4}\)và \(\frac{y}{5}=\frac{z}{6}\). Tính M=\(\frac{2x+3y+4z}{3x+4y+5z}\)
c) tìm x biết \(\frac{1}{4}.\frac{2}{6}.\frac{3}{8}.\frac{4}{10}...\frac{30}{62}.\frac{31}{64}=2^x\)
d)\(\frac{4^5+4^5+4^5+4^5}{3^5+3^5+3^5}.\frac{6^5+6^5+6^5+6^5+6^5+6^5}{2^5+2^5}=2x\)
2. Tính:P=\(1+\frac{1}{2}\left(1+2\right)+\frac{1}{3}\left(1+2+3\right)+...+\frac{1}{16}\left(1+2+..+16\right)\)
tìm x,y biết: \(\frac{1}{x}+\frac{1}{y}+\frac{2}{xy}=1\left(x,y\in Z,x\ne0,y\ne0\right)\)
Tìm x, y,z biết:
a) \(\frac{x}{y+z+1}=\frac{y}{x+z+2}=\frac{y}{x+y-3}\)
b) \(6\left(x-\frac{1}{y}\right)=3\left(y-\frac{1}{2}\right)=2\left(z-\frac{1}{x}\right)=xyz-\frac{1}{xyz}\)
Help me ! mik hứa sẽ tk
Cho x = \(\frac{\left(1-\frac{2}{3}\right)\cdot\left(-2+\frac{1}{4}\right)}{1-\frac{3}{4}+\frac{1}{6}}\)
và y = \(\frac{1-\frac{1}{1+\frac{4}{3}}}{2+\frac{1}{3}-\frac{3}{7}}\)
a/ Tính x + y
b/ x - y
Tính
A = \(\frac{0,6-\frac{1}{3}+\frac{3}{11}}{1,4-\frac{7}{9}+\frac{7}{11}}-\frac{\frac{1}{3}-0,25+\frac{1}{5}}{1\frac{1}{6}-0,875+0,7}\)
Tìm x,y,z biết:
\(\frac{x-1}{2}=\frac{y-2}{3}=\frac{z-3}{4}vàx-2y+3z=-10\)
\(\frac{x}{5}=\frac{y}{6}và2x^2-y^2=56\)