\(\Leftrightarrow2.\left(1-\frac{1}{3}+\frac{1}{3}-\frac{1}{5}+...+\frac{1}{47}-\frac{1}{49}\right)+4x=7.\left(1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+...+\frac{1}{98}-\frac{1}{99}\right)\)\(\Leftrightarrow2.\left(1-\frac{1}{49}\right)+4x=7.\left(1-\frac{1}{99}\right)\)
\(\Leftrightarrow2.\frac{48}{49}+4x=7.\frac{98}{99}\)
\(\Leftrightarrow\frac{96}{49}+4x=\frac{686}{99}\)
\(\Leftrightarrow4x=\frac{686}{99}-\frac{96}{49}\)
\(\Leftrightarrow4x=4,970109256\)
\(\Leftrightarrow x=4,970109256:4\)
\(\Leftrightarrow x=1,242527314\)
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