Question

Timf x \(\varepsilon\)Z

x.(x+3)=0

(x-2).(5-x)=0

 

Answer 1

x.(x+3) = 0

<=> x=0 hoặc x+3=0

<=> x=0 hoặc x=-3

(x-2).(5-x)=0

<=> x-2=0 hoặc 5-x=0

<=> x=2 hoặc x=5

Answer 2

a, x=0

hoặc x+3=0=>x=-3

b,x-2=0=>x=2

hoặc 5-x=0=>x=5

Answer 3

x.(x+3)=0

\(\Leftrightarrow\)x=0 Hoac x+3=0

\(\Leftrightarrow\)x=0 Hoac x=-3

Vay x\(\in\){0;-3)

(x-2).(5-x)=0

\(\Leftrightarrow\)x-2=0 Hoac 5-x=0

\(\Leftrightarrow\)x=2 Hoac x=5

Vay x\(\in\){2;5}