Question

timd x;y;z biết\(\frac{x}{y}\)=\(\frac{10}{9}\);\(\frac{y}{z}\)=\(\frac{3}{4}\)và x-y+z=78

Answer 1

b, Ta có: xy=109⇒x10=y9xy=109⇒x10=y9

yz=34⇒y3=z4⇒y9=z12yz=34⇒y3=z4⇒y9=z12

⇒x10=y9=z12=x−y+z10−9+12=7813=6⇒x10=y9=z12=x−y+z10−9+12=7813=6

⇒x=6.10=60⇒x=6.10=60

⇒y=6.9=54⇒y=6.9=54

⇒z=6.12=72

Answer 2

x/y=10/9 => x/10=y/9 (1)

y/z=3/4=> y/3=z/4=>y/9=z/12(2)

từ (1) (2) => x/10=y/9=z/12

=> x/10=y/9=z/12=(x-y+z)/(10-9+12)=78/13=6(t/c dãy ti số bằng nhau)

=>x=6*10=60

y=6*9=54

z=6*12=72

nếu thấy đung thì k cho mik nha cảm ơn bạn

Answer 3

Từ \(\frac{x}{y}=\frac{10}{9}\)\(\Rightarrow\frac{x}{10}=\frac{y}{9}\)(1)

Từ \(\frac{v}{z}=\frac{3}{4}\)\(\Rightarrow\frac{y}{3}=\frac{z}{4}\)\(\Rightarrow\frac{y}{9}=\frac{z}{12}\)(2)

Từ (1) và (2) \(\Rightarrow\frac{x}{10}=\frac{y}{9}=\frac{z}{12}=\frac{x-y+z}{10-9+12}=\frac{78}{13}=6\)

\(\Rightarrow x=6.10=60\);\(y=6.9=54\); \(z=6.12=72\)

Vậy x = 60; y = 54; z = 72