\(\left(\frac{5}{7}:y\right)\cdot\frac{14}{5}=\frac{7}{10}+\frac{1}{2}\)
\(\frac{5}{7}:y\cdot\frac{14}{5}=\frac{7}{10}+\frac{5}{10}\)
\(\frac{5}{7}\cdot\frac{14}{5}:y=\frac{12}{10}\)
\(2:y=\frac{12}{10}\)
\(y=2:\frac{12}{10}\)
\(y=2\cdot\frac{10}{12}\)
\(y=\frac{5}{3}\)
Câu này trong Violympic chứ gì !? Mình đọc lại đề bài thì thấy sai, mình sửa lại thành: Tìm y biết \(\left(\frac{5}{7}-y\right)\times\frac{14}{5}=\frac{7}{10}+\frac{1}{2}\)
\(\left(\frac{5}{7}-y\right)\times\frac{14}{5}=\frac{7}{10}+\frac{5}{10}\)
\(\left(\frac{5}{7}-y\right)\times\frac{14}{5}=\frac{12}{10}\)
\(\frac{5}{7}-y=\frac{12}{10}:\frac{14}{5}\)
\(\frac{5}{7}-y=\frac{3}{7}\)
\(y=\frac{5}{7}-\frac{3}{7}\)
\(y=\frac{2}{7}\)
Bạn Mai Thanh Xuân sai rồi nha
(5/7:y)*14/5=7/10+1/2
(5/7:y)*14/5=6/5
5/7:y=6/5:14/5
5/7:y=3/7
y=5/7:3/7
y=5/3
Vậy y=5/3
( 5/7 : y ) x 14/5 = 7/10 + 1/2
( 5/7 : y ) x 14/5 = 6/5
5/7 : y = 6/5 : 14/5
5/7 : y = 3/7
y = 5/7 : 3/7
y = 5/3
\(\left(\frac{5}{7}:y\right).\frac{14}{5}=\frac{7}{10}+\frac{1}{2}\)
\(\frac{5}{7}:y.\frac{14}{5}=\frac{7}{10}+\frac{1}{2}\)
\(\frac{5}{7}.\frac{14}{5}:y=\frac{12}{10}\)
\(2:y=\frac{12}{10}\)
\(y=2:\frac{12}{10}\)
\(y=2.\frac{10}{12}\)
\(y=\frac{5}{3}\)
Vậy \(y=\frac{5}{3}\)
